4cos^2(x)-5sin(x)+1=0

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Solution for 4cos^2(x)-5sin(x)+1=0 equation:


Simplifying
4cos2(x) + -5sin(x) + 1 = 0

Multiply cos2 * x
4cos2x + -5sin(x) + 1 = 0

Multiply ins * x
4cos2x + -5insx + 1 = 0

Reorder the terms:
1 + 4cos2x + -5insx = 0

Solving
1 + 4cos2x + -5insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4cos2x + -1 + -5insx = 0 + -1

Reorder the terms:
1 + -1 + 4cos2x + -5insx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4cos2x + -5insx = 0 + -1
4cos2x + -5insx = 0 + -1

Combine like terms: 0 + -1 = -1
4cos2x + -5insx = -1

Add '5insx' to each side of the equation.
4cos2x + -5insx + 5insx = -1 + 5insx

Combine like terms: -5insx + 5insx = 0
4cos2x + 0 = -1 + 5insx
4cos2x = -1 + 5insx

Divide each side by '4os2x'.
c = -0.25o-1s-2x-1 + 1.25ino-1s-1

Simplifying
c = -0.25o-1s-2x-1 + 1.25ino-1s-1

Reorder the terms:
c = 1.25ino-1s-1 + -0.25o-1s-2x-1

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